342 g of sucrose are dissolved in 18 g of water in a beaker the numbers of oxygen atoms in the solution are

3.42 g of sucrose are dissolved in 18 g of water in a beaker. The numbers of oxygen atoms in the solution are?

Answer?

Shruti Singh

Dil Naram, Dimaag Garam :D

Saturday, 28 November 2020 07:55 AM

Molar mass of sucrose = 342 g
No. of oxygen atoms in 342 g of ( $C_{12} H_{22} O_{11}$ ) $= 11 \times N_{A}$
$?$ No. of oxygen atoms in 3.42 g of ( $C_{12} H_{22} O_{11}$ ) $= \frac{1 1 \times N _{A} \times 3 . 4 2}{3 4 2}$ = $0.11 N_{A}$
No. of oxygen atoms in 18g of $H_{2} O$ $= 1 N_{A}$
$?$ Total no. of oxygen atoms in 3.42g of sucrose and 18g of water $= 0.11 N_{A} + 1 N_{A} = 1.11 N_{A} = 1.11 \times 6.02 \times 1 0^{23} = 6.68 \times 1 0^{23}$ .